poset의 뜻은 무엇인가요?
현재 검증된 한국어 뜻은 준비 중이며 영어 정의는 “(set theory, order theory) A partially ordered set.”입니다.
발음 /ˈpəʊsɛt/ · 품사 명사 (noun)
검증된 한국어 뜻을 준비 중입니다. 확인되지 않은 자동 번역은 표시하지 않습니다.
(set theory, order theory) A partially ordered set..
1973, Barbara L. Osofsky, Homological Dimensions of Modules, American Mathematical Society, →ISBN, page 76,
42. Definition. A poset (partially ordered set) (X, ≤) (usually written just X) is a set X together with a transitive, antisymmetric relation ≤ on X.
43. Definition. A linearly ordered set or chain is a poset (X, ≤), such that ∀a, b ∈ X, either a ≤ b or b ≤ a or a = b.1998, Yuri A. Drozd, Representations of bisected posets and reflection functors, Idun Reiten, Sverre O. Smalø, Øyvind Solberg (editors), Algebras and Modules II, American Mathematical Society (for Canadian Mathematical Society), page 153,
We construct a complete set of reflection functors for the representations of posets and prove that they really have the usual properties. In particular, when the poset is of finite representation type, all of its indecomposable representations can be obtained from some "trivial" ones via relations. To define such reflection functors, a wider class of matrix problem is introduced, called "representations of bisected posets".The combinatorial interest in posets is largely due to two unoriented graphs associated with a given poset: the comparability graph (which we shall not consider here) and the covering graph.poset의 의미, 어조와 문법이 전체 문장에 맞을 때 사용하세요. 동의어라도 모든 문장에서 바로 바꿔 쓸 수 있는 것은 아닙니다.
현재 검증된 한국어 뜻은 준비 중이며 영어 정의는 “(set theory, order theory) A partially ordered set.”입니다.
문장 속 의미에 따라 가까운 동의어가 달라집니다.
정확한 반대말은 사용된 의미에 따라 달라집니다.
1973, Barbara L. Osofsky, Homological Dimensions of Modules, American Mathematical Society, →ISBN, page 76, 42. Definition. A poset (partially ordered set) (X, ≤) (usually written just X) is a set X together with a transitive, antisymmetric relation ≤ on X. 43. Definition. A linearly ordered set or chain is a poset (X, ≤), such that ∀a, b ∈ X, either a ≤ b or b ≤ a or a = b.
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